What is the area (in sq cm) of a regular hexagon of side 32 cm?

1536 \(\sqrt{3}\)

Area of regular hexagon = 6 × area of one equilateral triangle.

                                       = 6 × \(\frac{\sqrt{3}}{4}\) a²

                                       = 6 × \(\frac{\sqrt{3}}{4}\) 32²

                                       = 6 × \(\frac{\sqrt{3}}{4}\) × 1024

                                       = 1536 \(\sqrt{3}\)