What is the area (in sq cm) of a regular hexagon of side 32 cm?
Answer & explanation
Correct answer: option 2
Area of regular hexagon = 6 × area of one equilateral triangle.
= 6 × \(\frac{\sqrt{3}}{4}\) a2
= 6 × \(\frac{\sqrt{3}}{4}\) 322
= 6 × \(\frac{\sqrt{3}}{4}\) × 1024
= 1536 \(\sqrt{3}\)