Assertion: The product of electrolysis of CuSO4 solution using inert electrode at anode is O2 and Cu at cathode.
Reason: pH of solution decreases during electrolysis.
Answer & explanation
Correct answer: option 1
CuSO4 solution using inert electrodes.
CuSO4 ⇔ Cu2+ + SO42-
H2O ⇔ H+ + OH-
At anode: 2OH- → H2O + \(\frac{1}{2}\)O2 + 2e-
At cathode: Cu2+ + 2e- → Cu
H+ interacts with SO42- to form H2SO4. So, pH of solution decreases during electrolysis.