Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Numbers, Quantification and Numerical Applications

Question:

How many kg of sugar costing ₹45 per kg must be mixed with 30 kg sugar costing ₹35 per kg so that there may be a gain of 12% by selling the mixture at ₹47.04 per kg ?

Options:

70 kg

75 kg

65 kg

60 kg

Correct Answer:

70 kg

Explanation:

The correct answer is option (1) : 70 kg

Let the C.P of mixture be ₹ x per kg

Given S.P = ₹ 47.04

Profit = 12%

$S.P= C.P+profit$

$47.04= x +12$% of x

$x=\frac{4704}{112}$

$= 42 $

Given $c= ₹35/kg$

$d= ₹45/kg$

$m= ₹42/kg$

quantity of cheaper sugar $= 30 kg $

$∴\frac{\text{quantity of cheaper sugar}}{\text{quantity of dearer sugar}}=\frac{45-12}{42-35}$

$\frac{30}{\text{quantity of dearer sugar}}=\frac{3}{7}$

quantity of dearer sugar $= 70 \, kg $

Hence, 70 kg of sugar costing ₹45 per kg should be mixed.