

Answer & explanation
Correct answer: option 4
$P(x)=-5x^2+125x+37500$
$P'(x)=-10x+125$
so $P'(x)=0⇒x=12.5$
for $0<x<12.5$
P(x) is strictly increasing


Correct answer: option 4
$P(x)=-5x^2+125x+37500$
$P'(x)=-10x+125$
so $P'(x)=0⇒x=12.5$
for $0<x<12.5$
P(x) is strictly increasing