The Value of $\frac{(2.8)^3 + (2.2)^3}{(28)^2 - 28 \times 22 + 484}$ is:
Answer & explanation
Correct answer: option 2
$\frac{(2.8)^3 + (2.2)^3}{(28)^2 - 28 \times 22 + 484}$
a3 + b3 = ( a + b ) ( a2 + b2 - ab )
( a + b ) = \(\frac{a^3 + b^3}{a^2 + b^2 - ab }\)
So, a = 2.8
b = 2.2
Then a + b= 2.8 + 2.2 = 5
Divide by 100 because of the decimal of the numerator = \(\frac{5}{100}\) = 0.05