Relation between rms voltage and peak voltage of an AC source is:

The correct answer is Option (3) → $V_{rms}=\frac{V_0}{\sqrt{2}}$

The relationship between the root mean square ($rms$) voltage $V_{rms}$ and the peak voltage $V_{peak}$ for -

$V_{rms}=\frac{V_{peak}}{\sqrt{2}}=\frac{V_0}{\sqrt{2}}$