Practicing Success
Practicing Success
CUET Preparation Today
Relation between rms voltage and peak voltage of an AC source is: |
$V_{rms}=\frac{2}{π}V_0$ $V_{rms}=V_0\sqrt{2}$ $V_{rms}=\frac{V_0}{\sqrt{2}}$ $V_{rms}=\frac{V_0}{2}$ |
$V_{rms}=\frac{V_0}{\sqrt{2}}$ |
The correct answer is Option (3) → $V_{rms}=\frac{V_0}{\sqrt{2}}$ |
