If a copper rod carries a direct current, the magnetic field due to it will be: |
only inside the rod only outside the rod both inside and outside of the rod neither inside nor outside the rod |
both inside and outside of the rod |
The correct answer is Option (3) → both inside and outside of the rod Magnetic field is both inside and outside of a conductor because direct current flow through the cross-section of copper rod. $B=\frac{μ_0Ir}{2πr^2}$ [Inside the conductor] [r < R] $B=\frac{μ_0I}{2πr}$ [Outside the conductor] [r > R] |