
Answer & explanation
Correct answer: option 1
$ N = \frac{P\lambda}{hc} = \frac{2\times 10^{-3}\times 5 \times 10^{-7}}{6.62\times 10^{-34}\times 3\times 10^8} = 5\times 10^{15}$

Correct answer: option 1
$ N = \frac{P\lambda}{hc} = \frac{2\times 10^{-3}\times 5 \times 10^{-7}}{6.62\times 10^{-34}\times 3\times 10^8} = 5\times 10^{15}$