A bus covers a distance of 10 km in 12 minutes. If its speed is decreased by 25 km/h,then the time (in minutes) taken by the bus to cover the same distance is: |
36 13 15 24 |
24 |
We know , Speed = \(\frac{Distance}{Time}\) 12 min =12× \(\frac{1}{60}\) hours Speed = \(\frac{10× 60 }{12}\) = 50 km/h Reduced speed = 50 - 25 = 25 km/h Time = \(\frac{Distance}{Speed}\) = \(\frac{10}{25}\) = 24 minutes |