A district has 10,24,000 inhabitants. If the population increases at the rate 2.5% per annum, find the number of inhabitants at the end of three years.

11,02,736

Total population = 102400

Population increase = 2.5% per annam

So it become  ,  100%  to 112.5% in every year 

ATQ

    102400×\(\frac{112.5}{100}\frac{112.5}{100}\frac{112.5}{100}\)

    = 1102736 Answer