A district has 10,24,000 inhabitants. If the population increases at the rate 2.5% per annum, find the number of inhabitants at the end of three years.
Answer & explanation
Correct answer: option 2
Total population = 102400
Population increase = 2.5% per annam
So it become , 100% to 112.5% in every year
ATQ
102400×\(\frac{112.5}{100}\frac{112.5}{100}\frac{112.5}{100}\)
= 1102736 Answer