Target Exam

CUET

Subject

Physics

Chapter

Alternating Current

Question:

Options:

a

b

c

d

Correct Answer:

b

Explanation:

$ I = a sin\omega t$

$I_{rms} = \frac{\int_0^\frac{T}{2}{I^2dt}}{\frac{T}{2}} = \frac{\int_0^\frac{T}{2}{a^2 sin^2\omega t dt}}{\frac{T}{2}} = \frac{2a^2}{3}$

$I_{rms} = \frac{a\sqrt 2}{\sqrt 3}$