Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Communication

Question:

Electric field in plane electromagnetic wave is given by-

Ey = 5 × 10–7 sin (0.25 × 103x + 2.5 × 1011t)

The magnetic field associated with it is

Options:

Bx = 0.5 × 10–7 sin (0.25 × 103x + 2.5 × 1011t)

Bx = 1.66 × 10–15 sin (0.25 × 103x + 2.5 × 1011t)

Bx = 9 × 10–7 sin (0.25 × 103x + 2.5 × 1011t)

Bx = 3.6 × 10–15 cos (0.25 × 103x + 2.5 × 1011t)

Correct Answer:

Bx = 1.66 × 10–15 sin (0.25 × 103x + 2.5 × 1011t)

Explanation:

We know,

\(\frac{E_0}{B_0}\) = c

∴ B0 = \(\frac{E_0}{c} = \frac{5×10^{-7}}{3×10^8}\) = 1.66 × 10-15

E and B should be perpendicular to each other and also perpendicular to direction of propagation. E is along y direction and direction of propagation is along x direction hence B is along z direction.

Bz = 1.66 × 10–15 sin (0.25 × 103x + 1011t)