Salicylaldehyde can be prepared by treating phenol with |
$CCl_4$ in presence of aqueous KOH $CO_2$ under pressure in the presence of sodium hydroxide solution. $NaNO_2$ and a few drops of concentrated $H_2SO_4$ $CHCl_3$ in the presence of aqueous NaOH |
$CHCl_3$ in the presence of aqueous NaOH |
The correct answer is Option (4) → $CHCl_3$ in the presence of aqueous NaOH On treating phenol with chloroform in the presence of sodium hydroxide, a –CHO group is introduced at ortho position of benzene ring. This reaction is known as Reimer - Tiemann reaction. The intermediate substituted benzal chloride is hydrolysed in the presence of alkali to produce salicylaldehyde. |