For a photodiode, the I-V characteristics for different illumination intensities $I_1, I_2, I_3$ and $I_4$ were plotted. Which of the following is correct?
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → $I_4>I_3>I_2>I_1$
In reverse bias, the p-type of the junction is connected to the negative terminal and n-type to positive terminal.
Due to this, the junction resistance is very high and practically no current flows through the circuit.