If \(\frac{secθ - tanθ}{secθ + tanθ}\) = \(\frac{3}{4}\), find sinθ .
Answer & explanation
Correct answer: option 3
\(\frac{secθ - tanθ}{secθ + tanθ}\) = \(\frac{3}{4}\)
By componendo & Dividendo concept:
\(\frac{secθ}{tanθ}\) = \(\frac{4 + 3}{4 - 3}\)
\(\frac{\frac{1}{cos}}{\frac{sin}{cos}}\) = \(\frac{7}{1}\)
\(\frac{1}{sinθ}\) = \(\frac{7}{1}\)
⇒ sinθ = \(\frac{1}{7}\) (where 1 → P and 7 → H)