Let \(f:\mathbb{R}\rightarrow\mathbb{R}\) defined by \(f(x)=5x+4\) then \(f^{-1}(x)\) is
Answer & explanation
Correct answer: option 1
\(f(x)=5x+4\)
so $y=5x+4⇒y-4=5x$
$⇒x=\frac{y-4}{5}$
$f^{-1}(x)=\frac{x-4}{5}$
Let \(f:\mathbb{R}\rightarrow\mathbb{R}\) defined by \(f(x)=5x+4\) then \(f^{-1}(x)\) is
Correct answer: option 1
\(f(x)=5x+4\)
so $y=5x+4⇒y-4=5x$
$⇒x=\frac{y-4}{5}$
$f^{-1}(x)=\frac{x-4}{5}$