The sum of the ages of A, B and C is 93 years, 10 years ago, the ratio of their ages was 2 : 3 : 4. What is the present age of B ?
Answer & explanation
Correct answer: option 3
Sum of Present age of A, B and C = 93
**Ten years ago age of every person was 10 years less than present age.**
Therefore,
Sum of age of A, B and C ten years ago was = 93 - 3(10) = 93 - 30 = 63
Ratio of age of A, B and C ten years ago is = 2 : 3 : 4 = 9 (Total)
9R = 63
1R = 7
B's age ten years ago = 3R = 3 × 7 = 21
B's present age = 21 + 10 = 31 years