Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

General Ability

Topic

Age Problems

Question:

The sum of the ages of A, B and C is 93 years, 10 years ago, the ratio of their ages was 2 : 3 : 4. What is the present age of B ?

Options:

21 years

28 years

31 years

38 years

Correct Answer:

31 years

Explanation:

Sum of Present age of A, B and C = 93

**Ten years ago age of every person was 10 years less than present age.**

Therefore,

Sum of age of A, B and C ten years ago was = 93 - 3(10) = 93 - 30 = 63

Ratio of age of A, B and C ten years ago is = 2 : 3 : 4 = 9 (Total)

9R = 63

1R = 7

B's age ten years ago = 3R = 3 × 7 = 21

B's present age = 21 + 10 = 31 years