The sum of the ages of A, B and C is 93 years. 10 years ago, the ratio of their ages was 2 : 3 : 4. What is the present age of B?
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 31 years
Ten years ago each of the three was 10 years younger, so their total age then was 30 years less than now. The ratio is applied to that total.
Total age 10 years ago: \(93-3\times10=63\) years
Ratio 2 : 3 : 4 has \(2+3+4=9\) parts, so one part \(=63\div9=7\) years
B’s age 10 years ago: \(3\times7=21\) years
B’s present age: \(21+10=31\) years