Target Exam

CUET

Subject

Section B2

Chapter

Numbers, Quantification and Numerical Applications

Question:

Match List – I with List – II.

List - I

List - II

 (A) The solution set of the inequality $-5 x>3, x \in R$, is 

 (I) $\left[\frac{20}{7}, \infty\right)$ 

 (B) The solution set of the inequality is, $\frac{-7 x}{4} ≤ -5, x \in R$ is, 

 (II) $\left[\frac{4}{7}, \infty\right)$ 

 (C) The solution set of the inequality $7 x-4 ≥ 0, x \in R$ is, 

 (III) $\left(-\infty, \frac{7}{5}\right)$ 

 (D) The solution set of the inequality $9 x-4<4 x+3, x \in R$ is,

 (IV) $\left(-\infty,-\frac{3}{5}\right)$ 

Choose the correct answer from the options given below:

Options:

(A)-(IV), (B)-(I), (C)-(II), (D)-(III)

(A)-(III), (B)-(IV), (C)-(II), (D)-(I)

(A)-(IV), (B)-(I), (C)-(III), (D)-(II)

(A)-(I), (B)-(IV), (C)-(II), (D)-(III)

Correct Answer:

(A)-(IV), (B)-(I), (C)-(II), (D)-(III)

Explanation:

The correct answer is Option (1) - (A)-(IV), (B)-(I), (C)-(II), (D)-(III)

$\text{(A)}\; -5x > 3 \Rightarrow x < -\frac{3}{5}$

$\Rightarrow (-\infty, -\frac{3}{5}) \Rightarrow \text{matches (IV)}$

$\text{(B)}\; \frac{-7x}{4} \le -5 \Rightarrow -7x \le -20 \Rightarrow x \ge \frac{20}{7}$

$\Rightarrow \left[\frac{20}{7}, \infty\right) \Rightarrow \text{matches (I)}$

$\text{(C)}\; 7x - 4 \ge 0 \Rightarrow x \ge \frac{4}{7}$

$\Rightarrow \left[\frac{4}{7}, \infty\right) \Rightarrow \text{matches (II)}$

$\text{(D)}\; 9x - 4 < 4x + 3 \Rightarrow 5x < 7 \Rightarrow x < \frac{7}{5}$

$\Rightarrow (-\infty, \frac{7}{5}) \Rightarrow \text{matches (III)}$

A–IV,\; B–I,\; C–II,\; D–III