The pair of linear equations $kx + 3y+ 1 = 0$ and $2x + y + 3 = 0$ intersect each other, if |
$K≠-6$ $k = 6$ $k ≠ 6$ $k ≠ -5$ |
$k ≠ 6$ |
The correct answer is Option (3) → $k ≠ 6$ Step 1: Condition for intersection Two lines: $a_1x + b_1y + c_1 = 0 \quad \text{and} \quad a_2x + b_2y + c_2 = 0$
$\frac{a_1}{a_2} \ne \frac{b_1}{b_2}$ Step 2: Apply to given lines
Parallel condition: $\frac{k}{2} = \frac{3}{1} ⇒k = 6$ So, lines are parallel if k = 6. Hence, lines intersect if: $k \ne 6$ |