The vector equation of the line passing through the point (-1, 5, 4) and perpendicular to the plane z=0 is :
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → $\vec{r}=-\hat{i}+5\hat{j}+ 4\hat{k} + \lambda \hat{k}$
$\vec a=-\hat i+5\hat j+4\hat k$
$\vec n=\hat k$ (to plane $z=0$)
So line is parallel to $\vec n$
so $\vec r=\vec a+λ\vec n$
eq: $\vec r=-\hat i+5\hat j+4\hat k+λ\hat k$