A person sold an article at a loss of 18%. Had he sold it for ₹960 more, he would have gained 12%. If the article is sold for ₹3,840, then how much is the profit percentage?

20%

The initial loss = 18%

Let, the cost price of the article = ₹ x

So, (\(\frac{82x}{100}\) ) + 960 = (\(\frac{112x}{100}\))

⇒ (\(\frac{112x}{100}\))- (\(\frac{82x}{100}\) ) = 960

⇒ (\(\frac{30x}{100}\) ) = 960

⇒ x = (\(\frac{960 × 100}{30}\) ) = 3200

∴ The cost price of the article =  3200

Required selling price =  3840

Then, profit = 3840 - 3200 =640

The profit percentage = (\(\frac{640}{3200}\))× 100 = 20%