Integrating factor of the differential equation $\frac{d y}{d x}+y=\frac{1+y}{x}$, is
Answer & explanation
Correct answer: option 2
We have, $\frac{d y}{d x}+\left(1-\frac{1}{x}\right) y=\frac{1}{x}$
Integrating factor = $e^{\int\left(1-\frac{1}{x}\right) d x}=e^{x-\log x}=\frac{1}{x} e^x$