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CUET
General Test
Quantitative Reasoning
Algebra
If $(x^3 + y^3)^{\frac{2}{3}}=(x^2+y^2)$, then the value of $\frac{x^2+y^2}{xy}$ x ≠ 0, y ≠ 0, is :
$\frac{2}{3}$
$x^2 + y$
1
$x + y^2$