Practicing Success
The difference between compound and simple interest of 2 years and 3 years on a certain rate of interest p.a. are Rs. 180 and Rs.552 respectively. Find the simple interest in 4 years on the same sum and at the same rate of interest. |
Rs. 4920 Rs. 8100 Rs. 9000 Rs .10800 |
Rs .10800 |
2 year diff. b/w CI and SI = B 3 year diff. b/w CI and SI = 3B + C ATQ, B = 180 and ⇒ 3B + C = 552 ⇒ 540 + C = 552 ⇒ C = 12 * Here, C = x% of B and B = x% of A* ⇒ 12 = x% of 180 ⇒ \(\frac{1}{15}\) = x% Now, ⇒ B = x% of A ⇒ 180 = \(\frac{1}{15}\) × A ⇒ A = 2700 = Simple Interest in 1 year ⇒ Simple Interest in 4 years = 2700 x 4 = 10800
OR The difference between SI and Ci in three years = 3(Interest on 1st year) + interest on SI earned in 2 years 552 = 3 x (180) + interest on SI earned in 2 years interest on SI earned in 2 years = 552 - 540 = 12 Rate of interest = \(\frac{12}{180}\) x 100 = \(\frac{20}{3}\)% Simple Interest in 1 year = \(\frac{180x180}{12}\) = 2700 Simple Interest in 4 years = 2700 x 4 = 10800 |