A Police officer sees a chain snatcher and runs to catch her from a distance of 50 metres. When the Police officer starts chasing the chain snatcher from a distance of 50 metres, the chain snatcher is running @ 2 metres per second. At the same time the Police Oficer is chasing the chain snatcher @ 4 metres per second. Find the distance covereed by the chain snatcher when the Police Officer shall be able to successfully catch her? |
50 metres 60 metres 150 metres 100 metres |
50 metres |
The correct answer is Option (1) → 50 metres Let the distance to be covered by the police officer to catch the chain snatcher be d meters. Let the time taken be t seconds. Relative speed of the police officer with respect to the chain snatcher: $= 4 - 2 = 2$ m/s The police officer starts 50 m behind, so: $\text{Time to catch} = \frac{50}{2} = 25$ seconds Distance covered by the chain snatcher in 25 seconds: $= 2 \times 25 = 50$ meters Answer: The chain snatcher covers 50 meters before being caught. |