Two events A and B will be independent if |
P(A) = P(B) P(A) + P(B) = 1 A and B are mutually exclusive events P(A’ B’) = [1 - P(A)][1 - P(B)] |
P(A’ B’) = [1 - P(A)][1 - P(B)] |
$\text{For independent events }A \text{ and } B,$ $P(A\cap B)=P(A)P(B).$ $P(A' \cap B')=P(A')P(B')=[1-P(A)][1-P(B)].$ $\text{Correct option is (D).}$ |