The value of $\sin ^2 60^{\circ} \cos ^2 45^{\circ}+2 \tan ^2 60^{\circ}-{cosec}^2 30^{\circ}$ is equal to:
Answer & explanation
Correct answer: option 2
sin²60º . cos²45º + 2 tan²60º - cosec²30º
= \(\frac{3}{4}\) × \(\frac{1}{2}\) + 2 × 3 - 4
= \(\frac{3}{8}\) + 2
= \(\frac{19}{8}\)