CUET Preparation Today
Study the adjoining picture and answer the following questions: |
The area of ΔABF is. |
$180m^2$ $90m^2$ $125m^2$ $60m^2$ |
$90m^2$ |
Here, we have right angle triangle ABF, where BF (base) = 10m, and AB (height) = AC - BC = 25 - 7 = 18m Area of ΔABF = \(\frac{1}{2}\) × base × height = \(\frac{1}{2}\) × BF × AB = \(\frac{1}{2}\) × 10 × 18 = 90m2 |
