Minimum excitation potential of Bohr's first orbit in hydrogen atom is
Answer & explanation
Correct answer: option 3
Excitation potential = $\frac{\text { Excitation energy }}{e}$
Minimum excitation energy corresponds to excitation from n = 1 to n = 2
∴ Minimum excitation energy in hydrogen atom $=-3.4-(-13.6)=+10.2~eV$ so minimum excitation potential = 10.2 eV.