If sinθ =  \(\frac{7}{25}\), then find the value of tanθ + cotθ .

1 0 \(\frac{168}{625}\) \(\frac{625}{168}\)

\(\frac{625}{168}\)

sinθ =  \(\frac{7}{25}\) ⇒ sinθ = \(\frac{7(P)}{25(H)}\) using Pythagoras theorem ,  Base = 24 tanθ + cotθ  = \(\frac{P}{B}\)  +  \(\frac{B}{P}\)  = \(\frac{7}{24}\)  + \(\frac{24}{7}\)    = \(\frac{625}{168}\)