How much work is done in moving a charge of 3.5 C across two points having a potential difference 14 V?
Answer & explanation
Correct answer: option 2
We know : $V = qW$
q : charge ; W = work done
$\Rightarrow 14 V = (3.5 C)(W)$
$\Rightarrow W = \frac{14 V}{3.5 C}$
= $4 J$