CUET Preparation Today
The function $x-\frac{\log(1+x)}{x}(x>0)$ is increasing in: |
(1, ∞) (0, ∞) (2, 2e) (1/e , 2e) |
(0, ∞) |
$f'(x)=\frac{x-\frac{\log(1+x)}{x}+\log(1+x)}{x^2}>0$ for increasing function $f'(x)>0$ $⇒x^2-\frac{x}{1+x}+\log(1+x)>0⇒x>0\,x∈(0, ∞)$ |
