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-- Mathematics - Section B1
Relations and Functions
Solution set of $2[x]^2-11[x]+12=0$ (where [·] represents greatest integer function) is
1
{1} ∪ [4, 5)
[4, 5)
[1, 2) ∪ [4, 5)
$2[x]^2-11[x]+12=0⇒(2[x]-3)([x]-4)=0$
$⇒[x]=\frac{3}{2}$ not possible and [x] = 4 ⇒ x ∈ [4, 5)