The electric field intensity due to an infinite thin plane sheet of surface charge density σ is: |
$+\frac{σ}{ε_0}$ $\frac{σ}{2ε_0}$ $\frac{-σ}{ε_0}$ $\frac{-2σ}{ε_0}$ |
$\frac{σ}{2ε_0}$ |
The correct answer is Option (2) → $\frac{σ}{2ε_0}$ The electric field intensity due to an infinite thin plane is, $E=\frac{σ}{2ε_0}$ |