Practicing Success

Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Algebra

Question:

If x + y + z = 18, xyz = 81 and xy + yz + zx = 90, then the value of $ x^3 + y^3 +z^3 +xyz $ is :

Options:

1321

1296

1225

1250

Correct Answer:

1296

Explanation:

x+ y3 + z3 - 3xyz = (x + y + z)[(x + y + z)2 - 3(xy + yz + zx)]

= x+ y3 + z3  - 3 × 81 = 18[(18)2 - 3 × 90]

= x+ y3 + z3  - 243 = 18[324 - 270]

= x+ y3 + z3  = 18 × 54 + 243 = 1215

So,

x+ y3 + z3 + xyz = 1215 + 81 = 1296