Equation of a curve that would cut x2 + y2 - 2x - 4y - 15 = 0 orthogonally can be ; where λ ∈ R.

$(y-2)=\lambda(x-1)$ $(y-1)=\lambda(x-2)$ $(y+2)=\lambda(x+1)$ $(y+1)=\lambda(x+2)$

$(y-2)=\lambda(x-1)$

Any line passing through the centre of the given circle would meet the circle orthogonally. Hence (1) is the correct answer.