If x - 2y = 3 and 2xy = 5, then find the value of $( x + 2y)^2$.

29

If x - y  = n

then 

then, x + y  = \(\sqrt {n^2 + 4xy}\)

we also know,

If K+l=n

then, $K^2+ l^2$ = n² – 2 × k × \(\frac{1}{k}\)

If x - 2y = 3

2xy = 5

Then find the value of $( x + 2y)$ = \(\sqrt {3^2 + 4×5}\) = \(\sqrt {29}\)

$( x + 2y)^2$ = (\(\sqrt {29}\))²

$( x + 2y)^2$ = 29