The focal length of the objective of a microscope is $f_o$ and that of the eye piece is $f_e$. The aperture of objective is $d_{o}$ and that of eye piece is $d_{e}$. Which of the following relation is correct? |
$f_{o}>f_{e}, d_{o}>d_{e}$ $f_{o}<f_{e}, d_{o}<d_{e}$ $f_{o}>f_{e}, d_{o}<d_{e}$ $f_{o}<f_{e}, d_{o}>d_{e}$ |
$f_{o}<f_{e}, d_{o}<d_{e}$ |
The correct answer is Option (2) → $f_{o}<f_{e}, d_{o}<d_{e}$ focal length of objective $(f_o)$ is less than the focal length of eyepiece $(f_e)$. i.e., $f_{o}<f_{e}$ Aperture of the objective $(d_o)$ is greater than the aperture of the eyepiece. i.e., $d_{o}<d_{e}$ |