Decreasing order of basicity for the following compounds: (A) Ethylamine Choose the correct answer from the options given below: |
(A), (B), (C), (D) (A), (C), (B), (D) (B), (A), (C), (D) (C), (B), (D), (A) |
(B), (A), (C), (D) |
The correct answer is Option (3) → (B), (A), (C), (D) Basicity depends on availability of lone pair on nitrogen. Electron donating alkyl groups increase basicity. Resonance delocalization decreases basicity. Detailed Explanation Option A: Ethylamine Primary amine with one alkyl group. Shows +I effect but less than diethylamine. Hence second. Option B: Diethylamine It is a secondary amine. Two ethyl groups donate electron density via +I effect. This increases availability of lone pair. Hence most basic. Option C: Ammonia No alkyl group. No +I effect. So less basic than alkyl amines. Option D: Benzenamine Lone pair is delocalized into benzene ring via resonance. Thus less available for protonation. Hence least basic. |