Consider the following hypothesis test:
$H_0:μ≤3432$
$H_a:μ> 3432$
A sample of 96 provided a sample mean $\bar x= 3648$ and sample standard deviation $s=802$ then the degree of freedom of t-distribution is:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 95
Given: H0: μ ≤ 3432, Ha: μ > 3432
Sample size: n = 96, Sample mean: $\bar{x} = 3648$, Sample standard deviation: s = 802
For t-test using sample standard deviation, the degrees of freedom is df = n - 1
df = 96 − 1 = 95
Degree of freedom = 95