Consider the following hypothesis test:
\(H_0: \mu \le 3432\)
\(H_a: \mu \gt 3432\)
A sample of 96 provided a sample mean \(\bar{x} = 3648\) and sample standard deviation \(s = 802\) then the degree of freedom of t-distribution is:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 95
In a one-sample t-test the population standard deviation is estimated by s, which uses up one degree of freedom. So the t statistic has n − 1 degrees of freedom:
\(\text{df} = n - 1 = 96 - 1 = 95\)
The sample mean and standard deviation are not needed to find the degrees of freedom.
CBSE Applied Mathematics (Class XII):
One Sample t-Test
