Consider the following hypothesis test:

$H_0:μ≤3432$
$H_a:μ> 3432$

A sample of 96 provided a sample mean $\bar x= 3648$ and sample standard deviation $s=802$ then the degree of freedom of t-distribution is:

95

The correct answer is Option (1) → 95

Given: H₀: μ ≤ 3432, H_a: μ > 3432

Sample size: n = 96, Sample mean: $\bar{x} = 3648$, Sample standard deviation: s = 802

For t-test using sample standard deviation, the degrees of freedom is df = n - 1

df = 96 − 1 = 95

Degree of freedom = 95