Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Applications of Derivatives

Question:

In the interval $(0, \pi / 2)$, the function $f(x)=\tan ^n x+\cot ^n x$ attains

Options:

the minimum value which is independent of n

a minimum value which is a function of n

the minimum value of 1

none of these

Correct Answer:

the minimum value which is independent of n

Explanation:

We have,

$f(x) =\tan ^n x+\cot ^n x$

$\Rightarrow f(x) =\left(\tan ^{n / 2} x-\cot ^{n / 2} x\right)^2+2 \geq 2$

Clearly, f(x) attains the minimum value 2 when $\tan ^{n / 2} x-\cot ^{n / 2} x=0$ i.e. $x=\frac{\pi}{4}$