Practicing Success
If $\left|\begin{array}{ccc}y+z & x & x \\ y & z+x & y \\ z & z & x+y\end{array}\right|=k(x y z)$, then k is equal to |
4 -4 Zero None of these |
4 |
Putting x = 1 y = 1, and z = 1 on both sides, we get k = 4 Hence (1) is the correct answer |