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Home/Practice questions/Chemistry
ChemistryInorganic: D and F Block Elements

Choose the Incorrect statement from the following:

Choose the Incorrect statement from the following:

Answer & explanation+

Correct answer: option 2

The correct answer is Option (2) → Diamagnetic substances are attracted by the applied magnetic field.

The magnetic behaviour of a substance depends on whether it has unpaired electrons. Diamagnetic substances (all electrons paired) are repelled by an applied magnetic field, paramagnetic substances (unpaired electrons) are attracted, and ferromagnetic substances are attracted very strongly.

  • Option (1) Cr2+ is a stronger reducing agent than Fe2+. — A correct statement. Cr (Z = 24) is [Ar]3d54s1, so \( \ce{Cr^{2+}} \) is 3d4 and \( \ce{Cr^{3+}} \) is 3d3 (half-filled t2g). E°(\( \ce{Cr^{3+}} \)/\( \ce{Cr^{2+}} \)) = −0.41 V is far lower than E°(\( \ce{Fe^{3+}} \)/\( \ce{Fe^{2+}} \)) = +0.77 V, so \( \ce{Cr^{2+}} \) gives up its electron much more easily.

  • Option (2) Diamagnetic substances are attracted by the applied magnetic field. — The incorrect statement. Diamagnetic substances (all electrons paired) are repelled by a magnetic field.

  • Option (3) E° value for the Mn3+/Mn2+ couple is much more positive than that for Cr3+/Cr2+ or Fe3+/Fe2+. — A correct statement. Mn (Z = 25) is [Ar]3d54s2, so \( \ce{Mn^{2+}} \) is 3d5 (half-filled, extra stable); \( \ce{Mn^{3+}} \) readily gains an electron to reach it, so E°(\( \ce{Mn^{3+}} \)/\( \ce{Mn^{2+}} \)) = +1.57 V.

  • Option (4) Ferromagnetism is an extreme form of paramagnetism. — A correct statement. Ferromagnetic substances also have unpaired electrons, but their moments are aligned in domains, so the attraction is much stronger.

NCERT (2026-27 edition):
Trends in the M3+/M2+ Standard Electrode Potentials – “… The comparatively high value for Mn shows that Mn2+(d5) is particularly stable, whereas comparatively low value for Fe shows the extra stability of Fe3+ (d5). …”

Chemical Reactivity and E° Values – “… The ions Ti2+, V2+ and Cr2+ are strong reducing agents and will liberate hydrogen from a dilute acid …”

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