A 1.5 m long straight wire carrying a current of 10 A experiences a force of 15 N, when placed in a magnetic field of 2 T. The angle between the direction of the current and the direction of the magnetic field is
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 30°
The force on a straight current-carrying wire in a uniform magnetic field depends on the angle between the current and the field.
\( \displaystyle F = BIl\sin\theta \)
\( \displaystyle 15\,\mathrm{N} = 2\,\mathrm{T} \times 10\,\mathrm{A} \times 1.5\,\mathrm{m} \times \sin\theta \)
\( 15 = 30\sin\theta \)
\( \sin\theta = 0.5 \)
\( \theta = 30^\circ \)
Note: A similar question was also asked in CUET (UG) 2025 on 14-05-2025 (Slot 2).