The corner points of a bounded feasible region are \( A(15,0),B(40,0),C(4,18) \) and \( D(6,12) \). If the objective function is \( z=20x+10y \), then the difference in maximum and minimum value of \( z \) is
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → 560
For a bounded feasible region, the maximum and minimum of z occur at corner points. The values of z = 20x + 10y there are:
At A(15, 0): z = 300
At B(40, 0): z = 800
At C(4, 18): z = 80 + 180 = 260
At D(6, 12): z = 120 + 120 = 240
Maximum = 800 and minimum = 240, so the difference is 800 − 240 = 560.