Which of the following will have the highest pKa value?
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → Phenol
pKa = −log Ka, so a higher pKa means a weaker acid.
Phenol is acidic because the phenoxide ion is stabilised by resonance. Any group that helps spread the negative charge further makes the phenol a stronger acid. The nitro group is strongly electron withdrawing:
At the ortho and para positions it withdraws electrons by both the −R (resonance) and −I effects; the negative charge can move onto the \( \ce{NO2} \) group, so acidity rises sharply.
At the meta position only the −I effect works, so acidity rises less.
So phenol, with no electron withdrawing group, is the weakest acid and has the highest pKa.
Why the other options are incorrect
Option (2) p-Nitrophenol — Incorrect. The para \( \ce{NO2} \) group stabilises the phenoxide by −R and −I effects; it is the strongest acid here, with the lowest pKa.
Option (3) m-Nitrophenol — Incorrect. The meta \( \ce{NO2} \) group acts only by its −I effect, but that still makes it more acidic than phenol.
Option (4) o-Nitrophenol — Incorrect. The ortho \( \ce{NO2} \) group acts by −R and −I effects; intramolecular hydrogen bonding makes it slightly weaker than the para isomer, but still much stronger than phenol.
NCERT (2026-27 edition):
Acidity of Phenols
| Compound | Formula | pKa |
|---|---|---|
| o-Nitrophenol | o–O2N–C6H4–OH | 7.2 |
| m-Nitrophenol | m–O2N–C6H4–OH | 8.3 |
| p-Nitrophenol | p-O2N–C6H4–OH | 7.1 |
| Phenol | C6H5–OH | 10.0 |
| o-Cresol | o-CH3–C6H4–OH | 10.2 |
| m-Cresol | m-CH3C6H4–OH | 10.1 |
| p-Cresol | p-CH3–C6H4–OH | 10.2 |
| Ethanol | C2H5OH | 15.9 |