If the numbers from 1 to 49 which are exactly divisible by 3 are arranged in ascending order, the minimum number being on top, which would come in eighth place from the bottom?
Answer & explanation
Correct answer: option 2
The correct answer is Option (2) → 27
The numbers from 1 to 49 divisible by 3 are 3, 6, 9, ..., 48. With the smallest on top, the largest, 48, is at the bottom, and moving up one place takes away 3.
1st from the bottom: 48
Each place higher is 3 less, so the 8th from the bottom is 7 places above 48
8th from the bottom: \(48-7\times3=27\)