Match the LIST-I with LIST-II
| LIST-I (Physical Quantity) | LIST-II (Dimensions) | ||
|---|---|---|---|
| A. | Magnetic permeability | I. | \( [\mathrm{L^{-1}A}] \) |
| B. | Magnetic flux | II. | \( [\mathrm{ML^{2}T^{-2}A^{-1}}] \) |
| C. | Magnetic intensity | III. | \( [\mathrm{MLT^{-2}A^{-2}}] \) |
| D. | Magnetic induction | IV. | \( [\mathrm{MT^{-2}A^{-1}}] \) |
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → A-III, B-II, C-I, D-IV
Work out the dimensions of magnetic induction first, from the force on a moving charge \( F = qvB \); the other quantities follow from their defining relations.
\( \displaystyle [B] = \frac{[F]}{[q][v]} = \frac{[\mathrm{MLT^{-2}}]}{[\mathrm{AT}][\mathrm{LT^{-1}}]} = [\mathrm{MT^{-2}A^{-1}}] \)
(A) Magnetic permeability — this matches (III) \( [\mathrm{MLT^{-2}A^{-2}}] \). From the field of a long solenoid, \( B = \mu nI \), with \( n \) in turns per metre:
\( \displaystyle [\mu] = \frac{[B]}{[n][I]} = \frac{[\mathrm{MT^{-2}A^{-1}}]}{[\mathrm{L^{-1}}][\mathrm{A}]} = [\mathrm{MLT^{-2}A^{-2}}] \)
(B) Magnetic flux — this matches (II) \( [\mathrm{ML^{2}T^{-2}A^{-1}}] \). Flux is field times area, \( \Phi = BA \), so \( [\mathrm{MT^{-2}A^{-1}}][\mathrm{L^{2}}] \).
(C) Magnetic intensity — this matches (I) \( [\mathrm{L^{-1}A}] \). \( H = nI \) is measured in ampere per metre.
(D) Magnetic induction — this matches (IV) \( [\mathrm{MT^{-2}A^{-1}}] \), as derived above.
Note: This question is from beyond the NCERT textbook and it appears to be out of the CUET 2026 Physics syllabus.