A is twice as good a worker as B, and together they finish a piece of work in 16 days. In how many days will A alone finish the work?
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → 24
Work done is shared in the ratio of efficiencies. A is twice as good as B, so in any time A does 2 parts of the work for every 1 part done by B.
Efficiencies A : B \(=2:1\), so together they work at \(2+1=3\) parts a day
Together they take 16 days, so the whole work is \(3\times16=48\) parts
A alone does 2 parts a day: \(\displaystyle\frac{48}{2}=\) 24 days