Arrange the following electromagnetic waves in increasing order of their wavelengths
(A) AM radio waves
(B) Ultraviolet rays
(C) Gamma rays
(D) Television waves
Choose the correct answer from the options given below:
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → (C), (B), (D), (A)
Wavelength increases in the order of the electromagnetic spectrum: gamma rays, X-rays, ultraviolet, visible, infra-red, microwaves, radio waves. Within radio waves, AM broadcast uses longer wavelengths than television (VHF/UHF).
\( \text{(C) Gamma rays: } \lambda \lt 10^{-3}\,\mathrm{nm} \)
\( \text{(B) Ultraviolet rays: } \lambda \approx 1\,\mathrm{nm} \text{ to } 400\,\mathrm{nm} \)
\( \text{(D) Television waves (54 MHz to 890 MHz): } \lambda \approx 0.3\,\mathrm{m} \text{ to } 5.5\,\mathrm{m} \)
\( \text{(A) AM radio waves (530 kHz to 1710 kHz): } \lambda \approx 175\,\mathrm{m} \text{ to } 570\,\mathrm{m} \)
Increasing order of wavelength: (C), (B), (D), (A).
NCERT (2026-27):
Electromagnetic Spectrum – “… We briefly describe these different types of electromagnetic waves, in order of decreasing wavelengths.”
Radio Waves – “… The AM (amplitude modulated) band is from 530 kHz to 1710 kHz. Higher frequencies upto 54 MHz are used for short wave bands. TV waves range from 54 MHz to 890 MHz.”
Ultraviolet Rays – “It covers wavelengths ranging from about 4 × 10–7 m (400 nm) down to 6 × 10–10 m (0.6 nm).”
Gamma Rays – “They lie in the upper frequency range of the electromagnetic spectrum and have wavelengths of from about 10–10 m to less than 10–14 m.”